Write a program that reads a, b, c, p, q and r. Let ax + by + c = 0 and px + qy + r = 0 be the equations
of two lines. Print their point of intersection.
Program:
#include<stdio.h>
int main()
{
int a,b,c;
int p,q,r;
printf("a,b,c: ");
scanf("%d%d%d",&a,&b,&c);
printf("p,q,r: ");
scanf("%d%d%d",&p,&q,&r);
int x,y;
x=(b*r-q*c)/(a*q-b*p);
y=(p*c-a*r)/(a*q-b*p);
printf("point of intersection (x,y)=(%d,%d)",x,y);
return 0;
}
of two lines. Print their point of intersection.
Program:
#include<stdio.h>
int main()
{
int a,b,c;
int p,q,r;
printf("a,b,c: ");
scanf("%d%d%d",&a,&b,&c);
printf("p,q,r: ");
scanf("%d%d%d",&p,&q,&r);
int x,y;
x=(b*r-q*c)/(a*q-b*p);
y=(p*c-a*r)/(a*q-b*p);
printf("point of intersection (x,y)=(%d,%d)",x,y);
return 0;
}
Sample input:
a,b,c: 4 8 12
p,q,r: 2 7 3
p,q,r: 2 7 3
Sample output:
point of intersection (x,y)=(-5,1)
point of intersection (x,y)=(-5,1)
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